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Science Dept.
Chemistry CHE 100 Notes
E. The Atom: the History of Discovery
- The Electron, e-
- Sir William Crookes (1832-1911) in 1879 discovered
cathode rays
- J.J. Thomson (1856-1940) in 1897 measured the ratio of
the charge of an electron over the mass of an electron,
e-/me = 1.76 x 108
coulombs/gram
- Millikan (1868-1953) in 1909 measured the
charge on an electron, -1.60 x 10-19 coulombs
- Knowing the ratio, e/m, and the charge, e, calculate the
mass of the electron
- The Proton, p+
- Goldstein in 1886 - "anode rays"
- J. J. Thomson
measured the ratio of the charge of a proton,
p+, over the mass of a proton, mp,
= p+/mp
- For the hydrogen nucleus, p+/mp
= 9.57 x 104 coulombs/gram
- Knowing the ratio of positive charge to mass, and the
charge, calculate the mass of the proton
- Radioactivity
- Becquerel - discoverd radioactivity
- Curies - discovered Po and Ra
- Rutherford - discovered and named alpha, beta and gamma rays
- Rutherford - definition of radioactivity
- Nobel Prizes
- Rutherford - discovers the Nuclear Atom
- Bombarded Au foil with alpha particles
- Gold Foil Experiment lead to three conclusions:
- Most of the matter of an atom is concentrated
in a small volume
- The positive charge of an atom is also
concetrated in a small volume of the atom
- Matter is made up mostly of empty space
- Geiger and his counter
- Marsden and his help
- Chadwick (1891-1974) in 1932 discoverd the neutron,
no, that Rutherford predicted
- The Bohr Atom
- The Simple Notion of Planetary Electons
- Related the line spectra to orbital jumps
- The Wave Mechanical Model of the Atom
- de Broglie: the Wave Nature of Matter
- Schrodinger: the Wave Mechanical Model of the Atom
- Energy Levels or Atomic Orbitals
- The Principal Energy Levels od 1, 2, 3, 4, 5, 6, 7
- Maximum number of electrons in any Principle
Energy Level is = 2n2
- Therefore:
- in Level #1 there are 2 electrons
- in Level #2 there are 8 electrons
- in Level #3 there are 18 electrons
- in Level #4 there are 32 electrons
- Arrangement of Electrons in Sublevels
- In Principle Energy Levels there may be s, p, d, and f
sublevels
- In the s sublevel there are 2 electrons
- In the p sublevel there are 6 electrons
- In the d sublevel there are 10 electrons
- In the f sublevel there are 14 electrons
- The "Stacking of Electrons"
- 1s2
- 2s22p6
- 3s23p63d10
- 4s24p64d104f14
- 5s25p65d105f14
- RULES of INFILLING: Draw diagonals through the sublevels from
the upper right to the lower left
- The first diagonal goes through the 1s2
- The second diagonal goes through the 2s2
- The third diagonal goes through the 2p6
and the 3s2
- The fourth diagonal goes through the 3p6
and the 4s2; N.B. it bypasses the 3d10!
- The Fifth diagonal goes through the 3d10,
the 4p6 and the 5s2
- These diagonals follow the rules of infilling
of the electons in an atom
- Some Examples
- 19K: 1S2 2S2
2P6 3S2 3P6
4S1
This element tends to lose one electron, the 4s1,
with the 3S2 3P6 left as the
outer electrons - a stable outer octet.
- 18Ar: 1S2 2S2
2P6 3S2 3P6
This element is an inert gas with a stable outer octet.
- 35Br: 1S2 2S2
2P6 3S2 3P6
4S2 3D10 4P5
This element tends to gain one electron to fill the 4P
level.
The electron gained
creates a stable outer octet of 4S2 4P6.
- 36Kr: 1S2 2S2
2P6 3S2 3P6
4S2 3D10 4P6
This element is an inert gas with a stable outer octet.
- Electron Dot Formulas - also known as Lewis Structures
- Electron Dot Formulas show only the electrons in the
outermost principal energy level
- For example: the element Na has 11 electrons, but only
the outermost electron is shown: Na.
The symbol Na will stand for the nucleus and the
10 innermost electrons
- For the A elements, write the symbol and place
as many dots as the column number
- How About a Quick Quiz?
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