HTML University
Science Dept.
Chemistry CHE 100 Notes
J. Chemical Calculations
- Definition of Atomic Mass Unit
- 1amu = 1/12 12C atom
- Calculation of Formula or Molecular Masses (or Weights)
- H2O
- NaCl
- H2CO3
- CH3OH
- Calculation of Moles
- Give the Atomic Weight of K in amu
- Give the Atomic Weight of Na in amu
- Notice the Weight Ratio between K and Na
- Would there be the same number of K atoms in 39 amu
of K
as there would be number of Na atoms in 22.99
amu of Na?
- Would there be the same number of K atoms in 39 grams
of K
as there would be number of Na atoms in 22.99
grams of Na?
- Avogadro's Number = 6.022 x 1023
- How many moles of O in 20.0 grams of O?
- How many moles of O2 in 20.0 grams of O2?
- Molar Volume Of A Gas
- One Mole of a Gas occupies 22.4 liters at STP
- Definition of STP or Standard Temperature and Pressure
- Standard Temperature is 0oC
- Standard Pressure is One Standard Atmosphere
(14.7 psi or 760 mm Hg)
- Calculation of Per Cent Composition of Compounds
- Na in NaCl
- Na = 22.99 amu; Cl = 35.45 amu
- [(Na)/(NaCl)] x 100 = Na%
- [(22.99 amu)/(22.99 + 35.45 amu)] x 100 = Na%
- [(22.99 amu)/(58.44 amu)] x 100 = 39.34% = Na% in NaCl
- H in H2O
- H = 1.0 amu; O = 16 amu
- [(2H)/(2H + O)] x 100 = H%
- [(2 amu)/(2 + 16 amu)] x 100 = H%
- [(2 amu)/(18 amu)] x 100 = 11.1% = H% in H2O
- Calculation of Simplest Formula
- Information: Na = 32.4%; S = 22.6%; O = 45.1%
- Change per cent to grams:
Na = 32.4g; S = 22.6g; O = 45.1g
- How many moles?
- of Na = 32.4g/22.99 = 1.41 moles Na
- of S = 22.6g/32.1 = 0.704 moles of S
- of O = 45.1g/16.0 = 2.82 moles of O
- Divide all three values of moles by the smallest
value
- for Na: 1.41/0.704 = 2
- for S: 0.704/0.704 = 1
- for O: 2.82/0.0704 = 4
- The Formula is: Na2SO4
- How About a Quick Quiz?